10x^2=40x=80

Solution for 10x^2=40x=80 equation:

10x^2=40x=80

We move all terms to the left:

10x^2-(40x)=0

a = 10; b = -40; c = 0;
Δ = b2-4ac
Δ = -402-4·10·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-40}{2*10}=\frac{0}{20}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+40}{2*10}=\frac{80}{20}
=4
$